get_class

>= 5.5

::class
fully qualified class name, instead of get_class

<?php
namespace my\library\mvc;

class Dispatcher {}

print Dispatcher::class; // FQN == my\library\mvc\Dispatcher

$disp = new Dispatcher;

print $disp::class; // parse error

A lot of people in other comments wanting to get the classname without the namespace. Some weird suggestions of code to do that - not what I would've written! So wanted to add my own way.

<?php
function get_class_name($classname)
{
    if ($pos = strrpos($classname, '\\')) return substr($classname, $pos + 1);
    return $pos;
}
?>

Also did some quick benchmarking, and strrpos() was the fastest too. Micro-optimisations = macro optimisations!

39.0954 ms - preg_match()
28.6305 ms - explode() + end()
20.3314 ms - strrpos()

(For reference, here's the debug code used. c() is a benchmarking function that runs each closure run 10,000 times.)

<?php
c(
    function($class = 'a\b\C') {
        if (preg_match('/\\\\([\w]+)$/', $class, $matches)) return $matches[1];
        return $class;
    },
    function($class = 'a\b\C') {
        $bits = explode('\\', $class);
        return end($bits);
    },
    function($class = 'a\b\C') {
        if ($pos = strrpos($class, '\\')) return substr($class, $pos + 1);
        return $pos;
    }
);
?>

People seem to mix up what __METHOD__, get_class($obj) and get_class() do, related to class inheritance.

Here's a good example that should fix that for ever:

<?php

class Foo {
 function doMethod(){
  echo __METHOD__ . "\n";
 }
 function doGetClassThis(){
  echo get_class($this).'::doThat' . "\n";
 }
 function doGetClass(){
  echo get_class().'::doThat' . "\n";
 }
}

class Bar extends Foo {

}

class Quux extends Bar {
 function doMethod(){
  echo __METHOD__ . "\n";
 }
 function doGetClassThis(){
  echo get_class($this).'::doThat' . "\n";
 }
 function doGetClass(){
  echo get_class().'::doThat' . "\n";
 }
}

$foo = new Foo();
$bar = new Bar();
$quux = new Quux();

echo "\n--doMethod--\n";

$foo->doMethod();
$bar->doMethod();
$quux->doMethod();

echo "\n--doGetClassThis--\n";

$foo->doGetClassThis();
$bar->doGetClassThis();
$quux->doGetClassThis();

echo "\n--doGetClass--\n";

$foo->doGetClass();
$bar->doGetClass();
$quux->doGetClass();

?>

OUTPUT:

--doMethod--
Foo::doMethod
Foo::doMethod
Quux::doMethod

--doGetClassThis--
Foo::doThat
Bar::doThat
Quux::doThat

--doGetClass--
Foo::doThat
Foo::doThat
Quux::doThat

If you are using namespaces this function will return the name of the class including the namespace, so watch out if your code does any checks for this. Ex:

namespace Shop;

<?php
class Foo
{
  public function __construct()
  {
     echo "Foo";
  }
}

//Different file

include('inc/Shop.class.php'); 

$test = new Shop\Foo();
echo get_class($test);//returns Shop\Foo
?>

Simplest way how to gets Class without namespace

<?php
namespace a\b\c\d\e\f;

class Foo {

  public function __toString() {
    $class = explode('\\', __CLASS__);
    return end($class);
  }
}

echo new Foo(); // prints Foo
?>

After reading the previous comments, this is the best I've done to get the final class name of a subclass:

<?php

class Singleton
{
   private static $_instances = array();
   protected final function __construct(){}
   
   /**
    * @param string $classname
    * @return Singleton
    */
   protected static function getInstance()
   {
      $classname = func_get_arg(0);
      if (! isset(self::$_instances[$classname]))
      {
         self::$_instances[$classname] = new $classname();
      }
      return self::$_instances[$classname];
   }
   
}

class Child extends Singleton
{
   /**
    * @return Child
    */
   public static function getInstance()
   {
      return parent::getInstance(get_class());
   }
}

?>

Subclasses must override "getInstance" and cannot override "__construct".

Need a quick way to parse the name of a class when it's namespaced? Try this:

<?php
namespace Engine;
function parse_classname ($name)
{
  return array(
    'namespace' => array_slice(explode('\\', $name), 0